# Ch-4-Prob-10-New-박종우

## 2130 days ago by matrix

 inverse of A = (1/dA)*adjA = [ 16 -7/2 3] [ 1 0 0] [ 4 -1 1] inverse of A = (1/dA)*adjA = [ 16 -7/2 3] [ 1 0 0] [ 4 -1 1]
 inverse of B = (1/dB)*adjB = [ 34/5 -202/5 -1 23/5 464/15] [ 0 2 0 0 -5/3] [ -27/5 141/5 1 -19/5 -322/15] [ -4/5 32/5 0 -3/5 -74/15] [ -4/5 27/5 0 -3/5 -59/15] inverse of B = (1/dB)*adjB = [ 34/5 -202/5 -1 23/5 464/15] [ 0 2 0 0 -5/3] [ -27/5 141/5 1 -19/5 -322/15] [ -4/5 32/5 0 -3/5 -74/15] [ -4/5 27/5 0 -3/5 -59/15]